In: Physics
a) What happens to the center spot as you slowly rotate the replica diffraction grating about its geometrical center? (Rotate here means to make the plane of the grating no longer perpendicular to the laser beam.)
b) What happens to the spots for n =1 and the spots for n = 2 as the grating is rotated?
c) Will you be able to observe the bright spots for n =1 and n = 2 if you spin the grating 90 ̊ while keeping the plane of the grating perpendicular to the laser beam? (In other words what once was the side of the grating, make it the bottom.)
Answer of a:
When the replica diffraction grating is rotated about its
geometrical centre, the centre spot is also rotated in the same
direction with same angle with respect to normal. When the replica
diffraction grating is rotated clockwise at degree with respect to normal,
the centre spot is also rotated toward clockwise at
degree. When the replica
diffraction grating is rotated counter clockwise at
degree with respect to normal,
the centre spot is also rotated toward counter clockwise at
degree.
Answer of b:
As the replica diffraction grating is rotated clockwise or anticlockwise, the centre spot is also rotated at the same angle with respect to normal. For this reason, the n =1 and n = 2 spots are also rotated because they are diffracted rays and make diffraction angle with the normal.
Answer of c:
When spin is rotated , the incidence light is
completely blocked by the grating and no n =1 or n = 2 spots are
observed.