In: Statistics and Probability
A researcher wants to determine if the average salaries for professors at all public and all private universities are different. He randomly selects 30 professors from public universities and independently 30 professors from private universities. The data are in thousands of dollars. The statistics are given below. Test the claim that the average salaries for all professors at public and private universities are different. Use α = 0.05 and fully justify! Mean 65.5 76.8 -11.3 Standard Deviation 24.3 24.3 24.3 Observations 30 30 30
The provided sample means are shown below:
Also, the provided sample standard deviations are:
and the sample sizes are n1=30 and n2=30.
(1) Null and Alternative Hypotheses
The following null and alternative hypotheses need to be tested:
Ho: μ1 = μ2
Ha: μ1 ≠ μ2
This corresponds to a two-tailed test, for which a t-test for two population means, with two independent samples, with unknown population standard deviations will be used.
(2) Rejection Region
Based on the information provided, the significance level is α=0.05, and the degrees of freedom are df = 58 . In fact, the degrees of freedom are computed as follows, assuming that the population variances are equal:
Hence, it is found that the critical value for this two-tailed test is t_c = 2.002 , for α=0.05 and df = 58
(3) Test Statistics
Since it is assumed that the population variances are equal, the t-statistic is computed as follows:
t = -1.801
(4) Decision about the null hypothesis
Since it is observed that |t| = 1.801 < tc=2.002, it is then concluded that the null hypothesis is not rejected.
Using the P-value approach: The p-value is p = 0.0769 , and since p = 0.0769 ≥0.05, it is concluded that the null hypothesis is not rejected.
(5) Conclusion
It is concluded that the null hypothesis Ho is not rejected. Therefore, there is not enough evidence to claim that the population mean μ1 is different than μ2, at the 0.05 significance level.
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