In: Statistics and Probability
You are interested in constructing a 99% confidence interval for the proportion of all caterpillars that eventually become butterflies. Of the 392 randomly selected caterpillars observed, 49 lived to become butterflies. Round answers to 4 decimal places where possible.
a. With 99% confidence the proportion of all caterpillars that lived to become a butterfly is between ___ and ____.
b. If many groups of 392 randomly selected caterpillars were observed, then a different confidence interval would be produced from each group. About ____ percent of these confidence intervals will contain the true population proportion of caterpillars that become butterflies and about ____ percent will not contain the true population proportion.
a)
Level of Significance, α =
0.01
Number of Items of Interest, x =
49
Sample Size, n = 392
Sample Proportion , p̂ = x/n =
0.125
z -value = Zα/2 = 2.576 [excel
formula =NORMSINV(α/2)]
Standard Error , SE = √[p̂(1-p̂)/n] =
0.0167
margin of error , E = Z*SE = 2.576
* 0.0167 = 0.0430
99% Confidence Interval is
Interval Lower Limit = p̂ - E = 0.125
- 0.0430 = 0.0820
Interval Upper Limit = p̂ + E = 0.125
+ 0.0430 = 0.1680
99% confidence interval is ( 0.0820 < p
< 0.1680 )
b)
About 99% percent of these confidence intervals will contain the true population proportion of caterpillars that become butterflies and about 1 percent will not contain the true population proportion