In: Statistics and Probability
Among 1,000 managers with degrees in business administration, the following data have been accumulated as to their fields of concentration.
Major |
Top Management |
Middle Management |
TOTAL |
Management |
280 |
220 |
500 |
Marketing |
120 |
80 |
200 |
Accounting |
150 |
150 |
300 |
TOTAL |
550 |
450 |
1000 |
1.Determine if the position in management is independent of field (major) of concentration.
2.State the null and alternative hypotheses for a contingency table test if we want to determine if the position in management is independent of field (major) of concentration.
3.State the decision rule for the critical value approach. Let alpha = 0.01.
4.Calculate the expected frequency for the cell “Marketing” and “Middle Management.”
5.If the Chi Square statistic is 5.253 what is your conclusion?
Ans:
H0:The position in management is independent of field (major) of concentration.
Ha:The position in management is not independent of field (major) of concentration.
Observed count(fo) | |||
Major | Top Management | Middle Management | TOTAL |
Management | 280 | 220 | 500 |
Marketing | 120 | 80 | 200 |
Accounting | 150 | 150 | 300 |
TOTAL | 550 | 450 | 1000 |
Expected count(fe) | |||
Major | Top Management | Middle Management | TOTAL |
Management | 275 | 225 | 500 |
Marketing | 110 | 90 | 200 |
Accounting | 165 | 135 | 300 |
TOTAL | 550 | 450 | 1000 |
Chi square=(fo-fe)^2/fe | |||
Major | Top Management | Middle Management | TOTAL |
Management | 0.091 | 0.111 | 0.202 |
Marketing | 0.909 | 1.111 | 2.020 |
Accounting | 1.364 | 1.667 | 3.030 |
TOTAL | 2.364 | 2.889 | 5.253 |
Chi square test statistic=5.253
df=(3-1)*(2-1)=2
critical chi square value=CHIINV(0.01,2)=9.210
Decision rule:
Reject H0,if Chi square test statistic>9.210
As,chi square test statistic=5.253 is less than 9.210,we fail to reject the null hypothesis and we can conclude that the position in management is independent of field (major) of concentration.