In: Statistics and Probability
Q1. Using the data provided for your group assignment estimate the simple regression
Y= Final_exam and X= assignment_grade. Each part of question is worth 2 marks.
Final_exam |
assignment_grade |
Tutorial_attend |
100 |
90 |
5 |
100 |
75 |
5 |
90 |
75 |
5 |
85 |
85 |
5 |
85 |
100 |
5 |
80 |
95 |
5 |
70 |
80 |
5 |
60 |
95 |
5 |
60 |
80 |
5 |
55 |
95 |
5 |
55 |
25 |
4 |
50 |
80 |
5 |
45 |
90 |
5 |
40 |
65 |
5 |
40 |
65 |
4 |
35 |
0 |
3 |
30 |
70 |
4 |
30 |
55 |
4 |
25 |
85 |
5 |
25 |
90 |
4 |
15 |
5 |
3 |
15 |
80 |
5 |
15 |
50 |
5 |
15 |
45 |
3 |
5 |
75 |
3 |
5 |
70 |
4 |
100 |
100 |
5 |
95 |
75 |
5 |
90 |
100 |
5 |
85 |
85 |
5 |
80 |
95 |
5 |
70 |
45 |
5 |
70 |
100 |
5 |
65 |
90 |
5 |
60 |
100 |
5 |
55 |
65 |
4 |
55 |
90 |
5 |
55 |
80 |
4 |
50 |
50 |
5 |
45 |
50 |
4 |
45 |
75 |
3 |
40 |
75 |
5 |
40 |
70 |
5 |
35 |
90 |
4 |
30 |
95 |
5 |
30 |
55 |
5 |
25 |
75 |
4 |
25 |
20 |
3 |
25 |
65 |
2 |
15 |
60 |
4 |
15 |
60 |
4 |
15 |
80 |
5 |
10 |
55 |
4 |
10 |
80 |
2 |
0 |
0 |
2 |
Answer(i):
Here we have Final_exam score as dependent variable and assignment grade as independent variable. Our expectation will be of a positive relationship between the dependent and independent variable as generally the final _exam score will increase with the increase in assignment grade.
Hence our expectation of sign of β1 is Positive.
Answer(ii):
We used excel data analysis tool to fit a simple regression model and the output in the tradition from is given below:
Intercept |
Assignment_grade |
|
Coefficients |
8.556 (10.349) |
0.537 (0.138) |
t statistic |
0.827 |
3.896 |
*values in parentheses are standard errors
The fitted regression equation is
Answer(iii):
We have to test
H0: β1 = 0
H1: β1 ≠ 0
we have the t statistic for β1
t=3.896
The critical value of t for two tailed alternative hypothesis at 0.05 level of significance with 53df is 2.005
The t statistic for β1 is 3.896 which is greater than tcritical = 2.005 and it suggest that we have enough evidence against H0 to reject it, so we reject the H0 at 5% level of significance and conclude that the β1 is highly significant.
Answer(iv):
We used excel data analysis tool to fit a multiple regression model and the output in the tradition from is given below:
Intercept |
assignment_grade |
Tutorial_attend |
|
Coefficients |
-35.753 (15.549) |
0.218 (0.153) |
15.338 (4.296) |
t statistic |
-2.300 |
1.421 |
3.570 |
*values in parentheses are standard errors
The fitted regression equation is
Answer(v):
We have to test
H0: β1 = 0
H1: β1 ≠ 0
we have the t statistic for β1
t=1.421
The critical value of t for two tailed alternative hypothesis at 0.05 level of significance with 53df is 2.005
The t statistic for β1 is 3.896 which is less than tcritical = 2.005 and it suggest that we do not have enough evidence against H0 to reject it, so we fail to reject the H0 at 5% level of significance and conclude that the β1 is not significant.