In: Finance
You are thinking of purchasing a house that costs $245,000. You have $13,000 in cash that you can use as a down payment but you need to borrow the rest of the purchase price. The bank is offering a 30 year mortgage that requires monthly payments and has an annual interest rate of 4.35% per year. What will your monthly payments be if you sign up for this mortgage? Draw the amortization schedule on a monthly basis using Excel. Calculate the total amount of interest paid throughout the life of the loan. Create a graph depicting the changes in the portions of interest and principal for each monthly payment throughout the life of the loan.
Suppose the interest rate decreases to 3.65% per year and the length of repayment decreases to 15 years. What will the new monthly payment be? Draw a new amortization schedule in a seperate Excel sheet. Calculate the total amount of interest paid throughout the life of the loan. How much do you save if you go with the 15 year mortgage versus the 30 year mortgage example above?
SITUATION- 1
LOAN $245000 - $13000 = $232000
YEARS = 30, INTEREST RATE = 4.35% P.A.
MONTHLY PAYMENTS = EMI = $1155
TOTAL INETERST PAYABLE = $183772
TOTAL PAYMENT = PRINCIPAL + INTEREST = $415772
FORMULA USED =
E = P×r×(1 + r)n/((1 + r)n - 1
WHERE, P= PRINCIPAL AMOUNT, r = RATE OF INTEREST, n = NO.OF YEARS
AMORTIZATION TABLE | ||||
LOAN $245000, DOWN PAYMENT $13000, INT. RATE. 4.35% P.A., YEARS 30 | ||||
YEAR | PRINCIPAL | INTEREST | PAYMENT | BALANCE |
1 | 3,843 | 10,016 | 13,859 | 2,28,157 |
2 | 4,014 | 9,845 | 13,859 | 2,24,143 |
3 | 4,192 | 9,667 | 13,859 | 2,19,951 |
4 | 4,378 | 9,481 | 13,859 | 2,15,574 |
5 | 4,572 | 9,287 | 13,859 | 2,11,002 |
6 | 4,775 | 9,084 | 13,859 | 2,06,227 |
7 | 4,987 | 8,872 | 13,859 | 2,01,240 |
8 | 5,208 | 8,651 | 13,859 | 1,96,032 |
9 | 5,439 | 8,420 | 13,859 | 1,90,592 |
10 | 5,681 | 8,178 | 13,859 | 1,84,912 |
11 | 5,933 | 7,926 | 13,859 | 1,78,979 |
12 | 6,196 | 7,663 | 13,859 | 1,72,783 |
13 | 6,471 | 7,388 | 13,859 | 1,66,312 |
14 | 6,758 | 7,101 | 13,859 | 1,59,554 |
15 | 7,058 | 6,801 | 13,859 | 1,52,495 |
16 | 7,371 | 6,488 | 13,859 | 1,45,124 |
17 | 7,698 | 6,161 | 13,859 | 1,37,426 |
18 | 8,040 | 5,819 | 13,859 | 1,29,386 |
19 | 8,397 | 5,462 | 13,859 | 1,20,989 |
20 | 8,770 | 5,090 | 13,859 | 1,12,219 |
21 | 9,159 | 4,700 | 13,859 | 1,03,060 |
22 | 9,565 | 4,294 | 13,859 | 93,495 |
23 | 9,990 | 3,869 | 13,859 | 83,506 |
24 | 10,433 | 3,426 | 13,859 | 73,073 |
25 | 10,896 | 2,963 | 13,859 | 62,177 |
26 | 11,379 | 2,480 | 13,859 | 50,797 |
27 | 11,884 | 1,975 | 13,859 | 38,913 |
28 | 12,412 | 1,447 | 13,859 | 26,501 |
29 | 12,963 | 896 | 13,859 | 13,538 |
30 | 13,538 | 321 | 13,859 |
0 |
SITUATION- 2
LOAN $245000 - $13000 = $232000
YEARS = 15, INTEREST RATE = 3.65% P.A.
MONTHLY PAYMENTS = EMI = $1676
TOTAL INETERST PAYABLE = $69621
TOTAL PAYMENT = PRINCIPAL + INTEREST = $301621
AMORTIZATION TABLE | ||||
LOAN $245000, DOWN PAYMENT $13000, INT. RATE. 3.65% P.A., YEARS 15 | ||||
YEAR | PRINCIPAL | INTEREST | PAYMENT | BALANCE |
1 | 11,837 | 8,271 | 20,108 | 2,20,163 |
2 | 12,276 | 7,832 | 20,108 | 2,07,887 |
3 | 12,732 | 7,376 | 20,108 | 1,95,155 |
4 | 13,204 | 6,904 | 20,108 | 1,81,951 |
5 | 13,694 | 6,414 | 20,108 | 1,68,257 |
6 | 14,203 | 5,905 | 20,108 | 1,54,054 |
7 | 14,730 | 5,378 | 20,108 | 1,39,324 |
8 | 15,277 | 4,831 | 20,108 | 1,24,048 |
9 | 15,844 | 4,264 | 20,108 | 1,08,204 |
10 | 16,432 | 3,676 | 20,108 | 91,772 |
11 | 17,042 | 3,066 | 20,108 | 74,731 |
12 | 17,674 | 2,434 | 20,108 | 57,057 |
13 | 18,330 | 1,778 | 20,108 | 38,727 |
14 | 19,010 | 1,098 | 20,108 | 19,716 |
15 | 19,716 | 392 | 20,108 | 0 |
TOTAL SAVINGS IF INTEREST RATE DECREASES TO 3.65% P.A. AND LENGTH OF 15YEARS
= $415772-$301621 = $114151