Question

Dependent T (T-test for paired) Table should look like this. Answer the three parts.

Shooting without noise	Shooting with noise	D (Difference)	D²

A. Write your research question and hypotheses

B. Test-Statistic (the t-ratio). Determine the degrees of freedom. df = (N – 1) .

C. Refer to the t-values in appendix B with df at the .05 significant level and at the .01 significant level in order to make the final conclusion.

NAME	NO NOISE	LOUD NOISE
Student1	3/10	6/10
Student2	1/10	6/10
Student3	2/10	1/10
Student4	4/10	4/10
Student5	4/10	3/10
Student6	9/10	7/10
Student7	1/10	1/10
Student8	3/10	3/10
Student9	0/10	3/10
Student10	4/10	3/10
Student11	5/10	3/10
Student12	4/10	6/10
Student13	2/10	2/10
Student14	5/10	7/10
Student15	4/10	2/10

Answer 1

Student	No Noise(X1   )	d1=(X1-17/50)	d12	Loud Noise (X 2 )	d 2=(X2-19/50)	d22
1	3/10	-2/50	.0016	6/10	11/50	.0484
2	1/10	-12/50	.0576	6/10	11/50	.0484
3	2/10	-7/50	.0196	1/10	-14/50	.0784
4	4/10	3/50	.0036	4/10	1/50	.0004
5	4/10	3/50	.0036	3/10	-4/50	.0064
6	9/10	28/50	.3136	7/10	16/50	.1024
7	1/10	-12/50	.0576	1/10	-14/50	.0784
8	3/10	-2/50	.0016	3/10	-4/50	.0064
9	0/10	-17/50	.1156	3/10	-4/50	.0064
10	4/10	3/50	.0036	3/10	-4/50	.0064
11	5/10	8/50	.0256	3/10	-4/50	.0064
12	4/10	3/50	.0036	6/10	11/50	.0484
13	2/10	-7/50	.0196	2/10	-9/50	.0324
14	5/10	8/50	.0256	7/10	16/50	.1024
15	4/10	3/50	.0036	2/10	-9/50	.0324
Total	51/10		0.6560	57/10		0.6040