For the matrix A, find (if possible) a nonsingular matrix P such
that P−1AP is diagonal. (If not possible, enter IMPOSSIBLE.) A = 2
−2 3 0 3 −2 0 −1 2 P = Verify that P−1AP is a diagonal matrix with
the eigenvalues on the main diagonal. P−1AP =
(a) Find the matrix representation for the orthogonal projection
Pr : R 4 → R 4 onto the plane P= span
1
-1
-1
1
-1
-1
1
1
(b) Find the distance of vector ~y =
2
0
0
4
from the plane P.
Diagonalize the matrix (That is, find a diagonal matrix D and an
invertible matrix P such that
A=PDP−1.
(Do not find the inverse of P). Describe all eigenspaces of A
and state the geometric and algebraic multiplicity of each
eigenvalue.
A=
-1
3
0
-4
6
0
0
0
1
Orthogonally diagonalize the matrix by finding an orthogonal
matrix Q and a diagonal matrix D such that QTAQ = D. (Enter each
matrix in the form [[row 1], [row 2], ...], where each row is a
comma-separated list.) A = 5 0 0 0 1 3 0 3 1 (D, Q) = $$ Incorrect:
Your answer is incorrect. Submission 2(0/1 points)Monday, November
25, 2019 10:01 PM CST Orthogonally diagonalize the matrix by
finding an orthogonal matrix Q and a diagonal...
Find the matrix P that diagonalizes A, and check your
work by computer P^-1AP. This matrix is
[-14 12]
[-20 17]
I've tried this problem, and I keep getting the eigenvalues of
λ=1, 2 and the eigenspace [4 5] for λ=1, and eigenspace [3 4] for
λ=2. However, whenever I check it with P^-1AP, it doesn't produce a
diagonal matrix.
(2) A matrix A is given. Find, if possible, an invertible matrix
P and a diagonal matrix D such that P −1AP = D. Otherwise, explain
why A is not diagonalizable.
(a) A = −3 0 −5
0
2 0
2
0 3
(b) A = 2 0 −1
1
3 −1
2
0 5
(c) A = 1 −1 2
−1
1 2
2
2 2
Consider the points below.
P(0, -3,0), Q(5,1,-2), R(5, 2, 1)
(a) Find a nonzero vector orthogonal to the plane through the points P, Q, and R.
(b) Find the area of the triangle PQR. (Recall the area of a triangle is one-half the area of the parallelogram.)
(a) Find a 3×3 matrix A such that 0 is the only eigenvalue of A,
and the space of eigenvectors of 0 has dimension 1. (Hint: upper
triangular matrices are your friend!)
(b) Find the general solution to x' = Ax.
PLEASE SHOW YOUR WORK CLEARLY.