Consider an infinitely long, straight coaxial cable consisting of a homogeneous cylindrical center conductor with radius...

Consider an infinitely long, straight coaxial cable consisting of a homogeneous cylindrical center conductor with radius a and a surrounding conductive tube (shield) with inner radius b.

The space between the center conductor and the screen is filled with a dielectric with e_r (epsilon r) = 1. In the inner conductor, a direct current I is distributed evenly over the cross section. In the outer conductor there is a corresponding return current. On the surface of the inner conductor there is a constant surface charge density Ρ_s,1 which determines how the power is transported in the cable.

(On the inside of the screen there is a corresponding constant surface charge density Ρ_s,2= -a / b * P_s,
1)

Determine the Poynting vector S = E x H for the cable.

Neglect the center conductor and the screen resistivities.
Tip: Calculate S and H in '' Normal '' way.

Expert Solution

genius_generous answered 2 years ago

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