In: Statistics and Probability
The Municipal Transit Authority claims that, on weekdays, fewer passengers ride the train that departs at 8 a.m. than the one that departs at 2 p.m. The following sample statistics were determined. The table shows the average number of riders for each train, after samples from random days were taken for each train.
n x bar s
Morning Train 30 323 41
Afternoon Train 45 356 45
Test at the a=.05 level of significance whether the data provide sufficient evidence to conclude that fewer passengers ride the morning.
a. State the Null and the Alternative Hypotheses, explaining which is mean 1 and which is mean 2. (2)
c. State the conclusion about the claim and how you made the decision. (4)
We have given
n | xbar | s | |
Morning Train | 30 | 323 | 41 |
Afternoon Train | 45 | 356 | 45 |
=.05
Null and the Alternative Hypotheses
Null Hypotheses:there is a no significant difference between population means of riders for each train,
Alternative Hypotheses: there is a significant difference between population means of riders for each train,
H0:μ1 = μ2
Ha: μ1 < μ2
Mean1=average number of riders for Morning train
Mean2=average number of riders for Afternoon train
Here we use two sample t-test
Hypothesis test
Formula:
=(323-356)/sqrt((41^2/30)+(45^2/45))
=-3.2831
Critical value of t at =.05 significance level for n1+n2-2=30+45-2=73 degrees of freedom is
t0.05,73=-1.666(left tailed)
c) since calculated |t| is grreater than |t_critical|
|-3.2831|=3.2831 > |-1.666|=1.666
i.e Hence we reject H0
Conclusion:
data provide sufficient evidence to conclude that fewer passengers ride the morning.