Question

Translate the following tasks into Hack C-Instructions:

1) Set D to A - 1
2) Set both A and D to A + 1
3) Set D to 19
4) Set both A and D to A + D
5) Set RAM[5034] to D - 1
6) Set RAM[543] to 171
7) Add 1 to RAM[7], and store result in D
8) Add 3 to RAM[12], and store result in D

Answer 1

Hack C-Instructions has the following syntax dest = comp ; jump     // dest ,= and jump mp are optional

Where: comp = 0 , 1 , ‐1 , D , A , !D , !A , ‐D , ‐A , D+1 , A+1 , D‐1, A‐1 , D+A , D‐A , A‐D , D&A , D|A,    M ,      !M ,       ‐M ,       M+1,           M‐1 ,        D+M, D‐M, M‐D, D&M, D|M

dest = M, D,  A, MD, AM, AD, AMD, or null

jump = JGT , JEQ , JGE , JLT , JNE , JLE , JMP, or null

1) Set D to A - 1

Ans:: D = A-1

2) Set both A and D to A + 1	AD=A+1
3) Set D to 19	@19 //A=19 D=A //D=A=19
4) Set both A and D to A + D	AD=A+D // AD means both A and B
5) Set RAM[5034] to D - 1	@5034 //A=5034 M=D-1 //M=RAM[5034] =D-1 , Note M=RAM[A]
6) Set RAM[543] to 171	@171 // A=171 D=A //D=171 @543 //A=543 M=D // M==RAM[A]=RAM[543]=D, RAM[543]=171
7) Add 1 to RAM[7], and store result in D	@7 //A=7 D=M+1 //D=RAM[A] +1=RAM[7] +1

8) Add 3 to RAM[12], and store result in D @3 // A=3

D=A //D=3

@12 //A=12

D=D+M //D=D + RAM[A]=D+RAM[12] =3 +RAM[12]