Question

In: Finance

MRE2. The file Credit Approval Decisions Coded provides information on credit history for a sample of...

MRE2. The file Credit Approval Decisions Coded provides information on credit history for a sample of banking customers. (18 pts)

a.         Use regression analysis to identify the best model to predict credit score based on the other             variables.

b.         Report and interpret R2 and Standard Error (SE) for the model developed in a.

c.         Interpret the regression coefficient(s) for the model developed in a.

DATA:

Coded Credit Approval Decisions
Homeowner Credit Score Years of Credit History Revolving Balance Revolving Utilization Decision
1 725 20 $             11,320 25% 1
1 573 9 $               7,200 70% 0
1 677 11 $             20,000 55% 1
0 625 15 $             12,800 65% 0
0 527 12 $               5,700 75% 0
1 795 22 $               9,000 12% 1
0 733 7 $             35,200 20% 1
0 620 5 $             22,800 62% 0
1 591 17 $             16,500 50% 0
1 660 24 $               9,200 35% 1
1 700 19 $             22,000 18% 1
1 500 16 $             12,500 83% 0
1 565 6 $               7,700 70% 0
0 620 3 $             37,400 87% 0
1 774 13 $               6,100 7% 1
1 802 10 $             10,500 5% 1
0 640 7 $             17,300 59% 0
0 523 14 $             27,000 79% 0
1 811 20 $             13,400 3% 1
0 763 2 $             11,200 70% 0
0 555 4 $               2,500 100% 0
0 617 9 $               8,400 34% 0
1 642 13 $             16,000 25% 1
0 688 3 $               3,300 11% 1
1 649 12 $               7,500 5% 1
1 695 15 $             20,300 22% 1
1 701 9 $             11,700 15% 1
0 635 7 $             29,100 85% 0
0 507 2 $               2,000 100% 0
1 677 12 $               7,600 9% 1
0 485 5 $               1,000 80% 0
0 582 3 $               8,500 65% 0
1 699 17 $             12,800 27% 1
1 703 22 $             10,000 20% 1
0 585 18 $             31,000 78% 0
1 620 8 $             16,200 55% 0
1 695 16 $               9,700 11% 1
1 774 13 $               6,100 7% 1
1 802 10 $             10,500 5% 1
0 640 7 $             17,300 59% 0
0 536 14 $             27,000 79% 0
1 801 20 $             13,400 3% 1
0 760 2 $             11,200 70% 0
0 567 4 $               2,200 95% 0
0 600 10 $             12,050 81% 0
1 702 11 $             11,700 15% 1
1 636 8 $             29,100 85% 0
0 509 3 $               2,000 100% 0
0 595 18 $             29,000 78% 0
1 733 15 $             13,000 24% 1

Solutions

Expert Solution

A-

Regression Analysis - Best Model (Y - Credit score X - Revolving Utilization )

SUMMARY OUTPUT
Regression Statistics
Multiple R 0.796420254
R Square 0.63428522
Adjusted R Square 0.626666162
Standard Error 55.00605103
Observations 50
ANOVA
df SS MS F Significance F
Regression 1 251886.1288 251886.1288 83.2498 0.0000
Residual 48 145231.9512 3025.6656
Total 49 397118.0800
Coefficients Standard Error t Stat P-value
Intercept 757.9223 13.9489 54.3357 0.0000
Revolving Utilization -220.7319 24.1921 -9.1241 0.0000

So Model Will be, Credit Score = 757.9223 - 220.7319 * Revolving Utilization

B - R Square - 0.63428522 or 63.428522%

Standard Error - 55.00605103

Interpretation

R square - 63.428533% change in Credit Score is explained by revolving utilization

Standard Error - The Standard error of 55.00605103 indicates the variability of predicted values from actual ones.

C.

Anova / F stat

Null Hypothesis - Credit Score is not dependent on the Independent Variables (i.e. Homeowner, Revolving Utilization, Revolving Balance, Years of credit history and decision)

Alternate Hypothesis - Credit Score is dependent on all or any of the Independent Variables (i.e. Homeowner, Revolving Utilization, Revolving Balance, Years of credit history and decision)

If P value of F stat > 0.05 - We Cannot Reject the Null Hypothesis

If P value of F stat < 0.05 - We Can Reject the Null Hypothesis

Since the P value of F stat is 0.0000, which is less than 0.05, so can reject the null hypothesis, Meaning that we should accept the alternate hypothesis. So we can say that Credit Score is dependent on all or any of the Independent Variables (i.e. Homeowner, Revolving Utilization, Revolving Balance, Years of credit history and decision).

Model is Significant

T stat

Null Hypothesis - Credit Score is not dependent on revolving utilization

Alternate Hypothesis - Credit Score is dependent on revolving utilization.

If P value of T stat > 0.05 - We Cannot Reject the Null Hypothesis

If P value of T stat < 0.05 - We Can Reject the Null Hypothesis

Since the P value of T stat is 0.0000, which is less than 0.05, so can reject the null hypothesis, Meaning that we should accept the alternate hypothesis. So we can say that Credit Score is dependent on revolving Utilization.

There is a 0% chance that the coefficient of revolving utilization is 0.

Revolving utilization is a significant variable for credit score



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