Find the equation of the plane tangent to the function f(x, y) = (x^2)(y^2) cos(xy) at...

Find the equation of the plane tangent to the function f(x, y) = (x^2)(y^2) cos(xy) at x = y = π / √ 2 . Using this linearization to approximate f, how good is the approximation L(x, y) ≈ f(x, y) at x = y = π / √ 2 ? At x = y = 0? At (x, y) = (π, π)?

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Expert Solution

Note:First i have calculated linearization equation at x=y=pi then x=y=pi/sqrt(2) then x=y=0

genius_generous answered 1 year ago

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