Case 2 Method: y" + 3y' + 2y = 7cos(x) - sin(x)

Case 2 Method:
y" + 3y' + 2y = 7cos(x) - sin(x)

Expert Solution

I have solved the given problem by the method of undetermined coefficients since no particular method name was given in the question. It can be solved by various other methods as well. If you require the solution by any other method, please do ask so that I can provide you with the same. If you find my answer helpful, kindly give me a thumbs up vote on my answer. For any other doubts or queries relating to the question or it's solution, please feel free to ask. Thanks!

Colby Messinger answered 1 year ago

use the method of variation of parameters to solve y''(x)-2y'(x)=exp(x)*sin(x)

x^2y''+2xy'+x^2y=0 Determine y if y1=(sin(x))/x

Solve the ODE y"+3y'+2y=(cosx)+(x^2)+(e^-1)

1) x2y'' - 8xy' - 8y =0 2) y''- 3y' - 2y = 10sin(x)

Given that a particular solution of 2y′′ +3y′ +y = x^2 +7x+8 is yp1=x^2+x+1 and that...

Given that a particular solution of 2y′′ +3y′ +y = x^2 +7x+8 is yp1=x^2+x+1 and that a particular solution of 2y′′ + 3y′ + y = 2sinx+4cosx is yp2=sinx-cosx, find a particular solution for 2y" +3y' +y =3x^2 + 21x + 24 -sinx -2cosx

Use the Method of Undetermined Coefficients to find the general solution 1) y''-3y'+2=cos(x) 2) y''-3y'+2=xe^x

Use method of variation of parameters to solve y'' + y = sin^2(x)

let f(x,y)=x^2y(2-x+y^2)-4x^2(1+x+y)^7+x^3y^2(1-3x-y)^8 find the coefficient of x^5y^3

f(x,y)=sin(2x)sin(y) intervals for x and y: -π/2 ≤ x ≤ π/2 and -π ≤ y ≤...

f(x,y)=sin(2x)sin(y) intervals for x and y: -π/2 ≤ x ≤ π/2 and -π ≤ y ≤ π find extrema and saddle points In the solution, I mainly interested how to findcritical points in case of the system of trigonometric equations (fx=0 and fy=0). ,

a) y''(x)-3y'(x)=8e3x+4sinx b) y''(x)+y'(x)+y(x)=0 c) y(iv)(x)+2y''(x)+y(x)=0

Question