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In: Physics

twoautomobiles of 840 kg and 1050 kg collide head on while moving at60 km/hr...

two automobiles of 840 kg and 1050 kg collide head on while moving at 60 km/hr in opposite directions. after they collision the automobiles remain locked together. find the velocity of the wreck immediately after the collision. also, find the kinetic energy of the two-car system before and after the collision

Solutions

Expert Solution

A)

Using law of conservation of momentum,

m1 v1 + m2 v2 = (m1 + m2) v

(840 x 60) - (1050 x 60) = (840 + 1050) v

V = 6.67 m/s (along 1050 kg car Direction)

B)

Initial KE = (0.5 x 840 x 60^2) + (0.5 x 1050 x 60^2) = 3402000 J

Final KE = 0.5 x (840 + 1050) x 6.67^2 = 42042.01 J

genius_generous answered 2 years ago
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