Question

Write a function decimalToBinary(n) that converts a positive decimal integer n to a string representing the corresponding binary number. Do the conversion by repeatedly dividing the number n by 2 using integer division, keepting track of the remainders, until the number is reduced to 0. The remainders written in reverse order form the binary number string.

Do integer division of 5 by 2, so that N//2 is 2 with remainder 1. Now divide 2 by 2 to get 1 with remainder 0. Next divide 1 by 2 to get 0 with remainder 1. Concatenating the remainders in reverse order makes 101, which is 5 in binary. Another example: N = 54. The division sequence is 54, 27, 13, 6, 3, 1, 0; and the remainder sequence is 0, 1, 1, 0, 1, 1. The remainders concatenated in reverse order produce: 110110, which is 54 in binary. Write a program which converts the values from 0 to 9 to binary, using the decimalToBinary(n) function. The output should look like:

0 is the binary of 0

1 is the binary of 1

10 is the binary of 2

11 is the binary of 3

100 is the binary of 4

101 is the binary of 5

110 is the binary of 6

111 is the binary of 7

1000 is the binary of 8

1001 is the binary of 9

Answer 1

Code is written in python

def decimalToBinary(n):

binary_num=[]

if(n==0):

return "0"

while (n > 0):

binary_num.append(str(n % 2));

n = n // 2;

return "".join(binary_num[::-1])

for i in range(10):

print(decimalToBinary(i)+" is the binary of "+str(i))