In: Chemistry
(a) How many moles of ammonium ions are in 0.795 g of ammonium carbonate?
(b) What is the mass, in grams, of 0.0507 mol of iron(III) phosphate?
(c) What is the mass, in grams, of 3.98*10^23 molecules of aspirin, C9H8O4?
(d) What is the molar mass of a particular compound if 0.090 mol weighs 6.38 g?
(a) Molar mass of ammonium carbonate,(NH4)2CO3
= 2[At.mass of N+(4xAt.mass of H)]+At.mass of C+(3xAt.mass of O)
= 2[14+(4x1)]+12+(3x16)
= 96 g/mol
Given mass of ammonium carbonate is 0.795 g
NUmber of moles , n = mass/molar mass
= 0.795g / 96 (g/mol)
= 828x10-3 moles
1 mole of ammonium carbonate contains 2 moles of NH4+ ions
828x10-3 moles of ammonium carbonate contains 2x828x10-3 moles of NH4+ ions
We know that one mole contains 6.023x1023 (avagadro number)ions
2x828x10-3 moles of NH4+ ion contains 2x828x10-3 x6.023x1023 = 9.97x1021 of NH4+ ions
(b) Molar mass of iron(III) phosphate,FePO₄ = At.mass of Fe + At.mass of P + (4xAt.mass of O)
= 55.8 + 31 + (4x16)
= 150.8 g/mol
Number of moles , n = mass/molar mass
Mass , m = number of moles x molar mass
= 0.0507 mol x 150.8 (g/mol)
= 7.645 g
(c) Molar mass of aspirin, C9H8O4 =(9xAt.mass of C)+(8xAt.mass of H) + (4xAt.mass of O)
= (9x12) + (8x1)+(4x16)
= 180 g/mol
We know that 1 mole of aspirin =180 g contains 6.023x1023 molecules
6.023x1023 molecules of aspirin weighs 180 g
3.98x1023 molecules of aspirin weighs M g
M = (3.98x1023 x 180) / (6.023x1023 )
= 118.9 g
(d) 0.090 mol of a compound weighs 6.38 g
1.0 mol of the compound weighs M g
M = ( 1.0x6.38) / 0.090
= 70.9 g
Therefore the molar mass of the compound is 70.9g/mol