Question

In: Statistics and Probability

You are given the following data, where X1 (GRE total score) and X2 (undergraduate GPA) are...

You are given the following data, where X1 (GRE total score) and X2 (undergraduate GPA) are used to predict Y (graduate GPA):

Y          X1       X2

3.6 135 2.6
4 130 2.6
3 105 2.4
3.3 115 2.7
3.2 105 3.1
3 100 3.2
2.7 110 3.8
3.8 125 3.6
4 145 3.2

Determine the following multiple regression values.

Report intercept and slopes for regression equation accurate to 3 decimal places:
    Intercept: a=
    Partial slope X1: b1=
    Partial slope X2: b2=


Report sum of squares accurate to 3 decimal places:
    SSreg=
    SSTotal=

Test the significance of the overall regression model (report F-ratio accurate to 3 decimal places and P-value accurate to 4 decimal places):
    F-ratio =
    P-value =

Report the variance of the residuals accurate to 3 decimal places:
    s2res=

Report the standard error of the partial slope estimate for GRE total along with the test statistic (report answers accurate to 3 decimal places):
    s(b1)=
    t1=

Solutions

Expert Solution

R Code

> y<-c(3.6,4,3,3.3,3.2,3,2.7,3.8,4)
> x1<-c(135,130,105,115,105,100,110,125,145)
> x2<-c(2.6,2.6,2.4,2.7,3.1,3.2,3.8,3.6,3.2)
> reg<-lm(y~x1+x2)
> summary(reg)

Call:
lm(formula = y ~ x1 + x2)

Residuals:
Min 1Q Median 3Q Max
-0.3760 -0.1186 -0.0393 0.1671 0.3134

Coefficients:
Estimate Std. Error t value Pr(>|t|)   
(Intercept) 0.709001 0.986610 0.719 0.49939   
x1 0.025744 0.006149 4.187 0.00577 **
x2 -0.122335 0.198772 -0.615 0.56086   
---
Signif. codes: 0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1

Residual standard error: 0.2699 on 6 degrees of freedom
Multiple R-squared: 0.7544,   Adjusted R-squared: 0.6726
F-statistic: 9.217 on 2 and 6 DF, p-value: 0.01481

Answers

Intercept: a= 0.709001
    Partial slope X1: b1=0.025744
    Partial slope X2: b2= -0.122335

F-statistic: 9.217 on 2 and 6 DF, p-value: 0.01481 =0.0418

SSE = 0.2699 =0.270

s(b1) =0.006149 =0.006 t1= 4.187


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