In: Statistics and Probability
Partial F Test. For this and the next 2 parts: A collector of
antique grandfather clocks believes that the price received for the
clocks at an antique auction increases with the age of the clock
(X1) and with the number of bidders (X2). Suppose the collector,
having observed many auctions, believes that the rate of increase
of the auction price with age will be driven upward by a large
number of bidders. As a result, the interaction term, X1X2, is
added to the model. Also, two second-order terms, X1-SQ and X2-SQ,
are included. Thus, the first order model is the "reduced model"
while the second-order model is considered the "complete model."
The models are summarized as follows:
First-order model: E(Y) = B0 + B1X1 + B2X2
Second-order model: E(Y) = B0 + B1X1 + B2X2 + B3X1X2 + B4X1-SQ +
B5X2-SQ
Since the second-order model contains all the terms of the
first-order model in addition to additional terms, it is said that
the two models are nested. You wish to test whether the
second-order model contributes more information for the prediction
of auction price. The regression output of the COMPLETE MODEL is
given below.
SUMMARY OUTPUT |
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Regression Statistics |
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Multiple R |
0.9799 |
|||||
R2 |
0.9602 |
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Adj. R2 |
0.9526 |
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SY.X |
85.6221 |
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n |
32 |
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ANOVA |
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df |
SS |
MS |
F |
P-value |
||
Regression |
5 |
4600584 |
920116.9 |
125.5078 |
0.0000 |
|
Residual |
26 |
190609.9 |
7331.152 |
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Total |
31 |
4791194 |
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Coeff. |
Std. Err. |
t Stat |
P-value |
Lower 95% |
Upper 95% |
|
Intercept |
-340.0331 |
760.6677 |
-0.4470 |
0.6586 |
-1903.6091 |
1223.5428 |
X1 |
3.4144 |
8.8971 |
0.3838 |
0.7043 |
-14.8739 |
21.7027 |
X2 |
13.6289 |
61.8639 |
0.2203 |
0.8274 |
-113.5343 |
140.7921 |
X1X2 |
1.1234 |
0.2303 |
4.8781 |
0.0000 |
0.6500 |
1.5968 |
X12 |
-0.0037 |
0.0273 |
-0.1358 |
0.8930 |
-0.0599 |
0.0525 |
X22 |
-4.1290 |
2.1331 |
-1.9357 |
0.0638 |
-8.5136 |
0.2555 |
Part A.
If the second-order terms contribute to the model, then
The sum of squares error for the reduced model (SSER) should be much smaller than the sum of squares error for the complete model (SSEC) in a significant way. |
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The sum of squares error for the complete model (SSEC) should be much smaller than the sum of squares error for the reduced model (SSER) in a significant way. |
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the difference, (SSER - SSEC), will be very small and insignificant |
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None of the above |
Part B.
The sum of squares error for the REDUCED MODEL 514,034.5. Compute the F statistic to test the null hypothesis that the coefficients of the second-order terms are equal to zero in a partial F test.
14.71 |
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0.91 |
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7,331.15 |
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2.98 |
Part C.
Would you conclude, at the 0.05 level, that the inclusion of the second-order terms contributes significantly to the prediction of antique clock prices?
Yes, F value from Exhibit 2 is significant |
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Yes, F value for the difference, (SSER - SSEC), is significant |
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Yes, F value from Exhibit 1 is significant |
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No, p value for the difference, (SSER - SSEC), is greater than 0.05 |
PART A) The sum of squares error for the reduced mode should be much smaller than the sum of square error for the complete model.
PART B) F test is 14.71
PART C) YES Fvalue for the difference is significant