Question

A severely myopic patient has a far point of 7.75 cm. By how many diopters should the power of his eye be reduced in laser vision correction to obtain normal distant vision for him? (Assume a lens-to-retina distance of 2.00 cm.)

Answer 1

di =2.00 cm

do = 7.75 cm

'

The power of a normal eye is 50 D

So, in order for him to have normal vision, the laser vision correction should reduce the power of his eye by

P = 62.90D − 50D

P = 12.9 D ~ 13 D