A severely myopic patient has a far point of 7.75 cm. By how many diopters should...

A severely myopic patient has a far point of 7.75 cm. By how many diopters should the power of his eye be reduced in laser vision correction to obtain normal distant vision for him? (Assume a lens-to-retina distance of 2.00 cm.)

Solutions

Expert Solution

di =2.00 cm

do = 7.75 cm

The power of a normal eye is 50 D

So, in order for him to have normal vision, the laser vision correction should reduce the power of his eye by

P = 62.90D − 50D

P = 12.9 D ~ 13 D

genius_generous answered 2 years ago

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