In: Statistics and Probability
An astronomer is investigating whether or not there is a relationship between the type of a planet and the shape of its orbit. There are three types of planets: rocky, gas giant, and ice giant, and two types of orbit: circular and elliptical. The astronomer gets information on observed planets and lists their characteristics, they assume that the planets that have been observed are a simple random sample of all planets. Counts for the different kinds of planets are given below
Rocky |
Gas Giant |
Ice Giant | Total | |
Circular Orbit | 48 | 62 | 53 | 163 |
Elliptical Orbit | 99 | 102 | 79 | 280 |
Total | 147 | 164 | 132 | 443 |
a) State the astronomer's hypotheses.
b) Compute the test statistic and p-value for this test.
c) Reach your conclusion for the test at the .05 significance level.
d) The astronomer has a theory that fewer than half of all rocky planets have circular orbits. What kind of statistical test could be used to answer that question.
a)
The null and alternate hypothesis are:
H0: There is no relationship between the type of a planet and
the shape of its orbit.
Ha: There is a relationship between the type of a planet and the
shape of its orbit.
b)
Observed (Oi):
Rocky | Gas Giant | Ice Giant | TOTAL | |
Circular orbit | 48 | 62 | 53 | 163 |
Elliptical orbit | 99 | 102 | 79 | 280 |
TOTAL | 147 | 164 | 132 | 443 |
Now, Expected frequency = [(Row total) x (Column total)] / Table total
Expected (Ei):
Rocky | Gas Giant | Ice Giant | TOTAL | |
Circular orbit | 60.343 | 48.569 | 163 | |
Elliptical orbit | 92.912 | 103.657 | 83.431 | 280 |
TOTAL | 147 | 164 | 132 | 443 |
Test statistic value =
The p-value is given by:
c)
Since p-value is greater than 0.05, so we do not have sufficient evidence to reject the null hypothesis H0.
Thus we conclude that there is no relationship between the type of a planet and the shape of its orbit.
d)
This a test for true proportion. So, a z-test should be used.