how many photons are produced in a laser pulse of 0.558 J at 431 nm?

Expert Solution

Energy of 1 photon =h*c/lambda

= (6.626*10^-34)*(3*10^8) / (431*106-9 )

= 4.612*10^-19 J

Total energy = 0.558 J

Number of photon = total energy /energy of 1 photon

=0.558 / (4.612*10^-19)

= 1.21*10^18 photons

Answer: 1.21*10^18 photons

queen_honey_blossom answered 2 years ago

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