Question

(IN C)

What are the contents of the array after the for-loop in the following code?

int array[ SIZE ][ SIZE ] = { { 4, 5, 6, 7, 8 },

{ 1, 2, 3, 4, 5 },

{ 3, 6, 7, 8, 9 },

{ 2, 3, 4, 5, 6 },

{ 5, 6, 7, 8, 9 } };

int i;

int *ptr = array[ 0 ];

for( i = 0; i < SIZE * SIZE; i++ ) {

if( i % SIZE < 2 ) {

*( ptr + i ) = 0;

}

else if( i % SIZE == 2 ) {

*( ptr + i * SIZE ) = 100;

}

}

Answer 1

if( i % SIZE < 2 ) {

          *( ptr + i ) = 0;

}

The above condition make the memory address 0,1,5,6,10,11,15,16,20,21 is set to 0

else if( i % SIZE == 2 ) {

          *( ptr + i * SIZE ) = 100;

}

The above condition is satisfied when i=2,7,12,17,22

the index which are changed is 10,35,60,85,100

but the index 10 is overwritten by first if condition to 0

So the final output is