if mixture is composed of 76.3% c-12 and 23.7% of c-14 what is the average atomic...

if mixture is composed of 76.3% c-12 and 23.7% of c-14 what is the average atomic mass

Expert Solution

The portion of average mass of C-12 is = the percentage abundance of C-12 x atomic mass of C-12

= (76.3/100) x 12

= 9.156

The portion of average mass of C-14 is = the percentage abundance of C-14 x atomic mass of C-14

= (23.7/100) x 14

= 3.318

So total mass is = The portion of average mass of C-12 + The portion of average mass of C-14

= 9.156 + 3.318

= 12.474

Therefore the average atomic mass is 12.474 amu

queen_honey_blossom answered 2 years ago

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