In: Chemistry
HX is a weak acid that reacts with water according to the following equation: HX(aq) + H2O(l) H3O1+(aq) + X1-(aq) Ka = 3.16e-07 What is the equilibrium concentration of hydronium ion in a solution that is 0.0538 M in HX and 0.116 M in X1- ion?
HX (aq) + H2O(l) --------------------> H3O+(aq) + X-(aq)
0.0538 0 0.116
0.0538 - x x 0.116+x
Ka = x (0.116+x) / 0.0538 - x
3.16 x 10^-7 = x (0.116+x) / 0.0538 - x
x = 1.47 x 10^-7
[H3O+] = 1.47 x 10^-7 M