Question
In: Physics
When ultraviolet light with a wavelength of 400 nm falls on a certain metal surface, the...
When ultraviolet light with a wavelength of 400 nm falls on a certain metal surface, the maximum kinetic energy of the emitted photoelectrons is 1.10 eV.
What is the maximum kinetic energy Ko of the photoelectrons when
light of wavelength 320 nm falls on the same surface?
Use h = 6.63
Solutions
Expert Solution
Wavelength ? = 400 nm = 400*10^-9 m = 4*10^-7 m
Energy of photon E = hc/? = (6.63*10^-34*3*10^8)/(4*10^-7)
= 4.972*10^-19 J = (4.972*10^-19)/(1.602*10^-19)
= 3.103 eV
Maximum kinetic energy Ko = 1.10 eV
Work function of the metal surface W = E - Ko = 3.103 - 1.10 = 2.003 eV
New wavelength ?' = 320 nm = 320*10^-9 m
Energy of the incident photon E' = 6.416*10^-19 J = 4.004 eV
Maximium Kinetic energy Ko' = E' - W
= 4.004 - 2.003 = 2.001 eV = 3.205*10^-19 J
genius_generous answered 2 years agoRelated Solutions
When ultraviolet light with a wavelength of 400 nm falls on a certain metal surface, the...
When ultraviolet light with a wavelength of 400 nm falls on a
certain metal surface, the maximum kinetic energy of the emitted
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