In: Statistics and Probability
Suppose a sample of 21 is drawn from a population that has a continuous random variable x that is well-approximated by a normal distribution. If the sample mean is given by ?̅= 202.4 with standard deviation s = 26 find
a) a 98% Confidence interval for ?. Be sure to include pictures and graphs that would support your work.
b) State specifically how you would interpret this interval.
n = 21
S = 26
x̅ = 202.4
Standard Error = S / √n
= 26 / √21
= 5.6736
Standard Error = 5.6736
Confidence Interval = Mean + - Margin Error
Confidence Interval = Mean + - ( Critical value* Standard Error)
For Critical value:
ꭤ = 1 – 0.98 = 0.02
P value = 1 – (ꭤ/ 2)
= 1 – (0.02/2)
= 1 – 0.01
= 0.99
From Z table we get
Critical value = 2.33
Now,
Confidence Interval = Mean + - ( Critical value* Standard Error)
= 202.4 + - ( 2.33 * 5.6736)
= 202.4 + - 13.2194
= 189.1806 and 215.6194
Confidence Interval = 189.1806 and 215.6194