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A mixture of 0.02958 mol of O2, 0.01705 mol of NOCl, 0.03162 mol of NO2, and...

A mixture of 0.02958 mol of O2, 0.01705 mol of NOCl, 0.03162 mol of NO2, and 0.008375 mol of Cl2 is placed in a 1.0-L steel pressure vessel at 2458 K.

The following equilibrium is established: 1 O2(g) + 2 NOCl(g) 2 NO2(g) + 1 Cl2(g)

At equilibrium 0.005233 mol of Cl2 is found in the reaction mixture.

(a) Calculate the equilibrium partial pressures of O2, NOCl, NO2, and Cl2.

Peq(O2) = .

Peq(NOCl) = .

Peq(NO2) = .

Peq(Cl2) = .

(b) Calculate KP for this reaction.

KP = .

Solutions

Expert Solution

queen_honey_blossom answered 3 years ago
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