The work function for aluminum is 4.08 eV. (a) What is the cutoff frequency of light...

The work function for aluminum is 4.08 eV.

(a) What is the cutoff frequency of light incident on an aluminum target that releases photoelectrons from its surface?

(b) Find the corresponding cutoff wavelength.

(c) If photons of energy 5.0 eV are incident on an aluminum target what is the maximum kinetic energy of the ejected photoelectrons?

(d) what is the maximum velocity of a photoelectron traveling from the anode to the cathode of a photocell?

(e) If a blue beam with ? = 500 nm hits the aluminum target, what will be the kinetic energy of the emitted photoelectrons?

Expert Solution

genius_generous answered 2 years ago

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