size 7mm 6mm 5mm 4mm 3mm total dead 2 24 1428 16 9 1479 alive 0...

size	7mm	6mm	5mm	4mm	3mm	total
dead	2	24	1428	16	9	1479
alive	0	1	31	0	0	32

Do a 2 sample t-Test (independent) with this data.

Expert Solution

Given that,
mean(x)=295.8
standard deviation , s.d1=632.9717
number(n1)=5
y(mean)=6.4
standard deviation, s.d2 =13.7586
number(n2)=5
null, Ho: u1 = u2
alternate, H1: u1 != u2
level of significance, α = 0.05
from standard normal table, two tailed t α/2 =2.776
since our test is two-tailed
reject Ho, if to < -2.776 OR if to > 2.776
we use test statistic (t) = (x-y)/sqrt(s.d1^2/n1)+(s.d2^2/n2)
to =295.8-6.4/sqrt((400653.173/5)+(189.29907/5))
to =1.0221
| to | =1.0221
critical value
the value of |t α| with min (n1-1, n2-1) i.e 4 d.f is 2.776
we got |to| = 1.02211 & | t α | = 2.776
make decision
hence value of |to | < | t α | and here we do not reject Ho
p-value: two tailed ( double the one tail ) - Ha : ( p != 1.0221 ) = 0.365
hence value of p0.05 < 0.365,here we do not reject Ho
ANSWERS
---------------
null, Ho: u1 = u2
alternate, H1: u1 != u2
test statistic: 1.0221
critical value: -2.776 , 2.776
decision: do not reject Ho
p-value: 0.365
we do not have enough evidence to support the claim that difference of means between dead and alive.

orchestra answered 2 years ago

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