Determine the theoretical yield in mL when 1.5 mL of 3,3-dimethyl-2-butanol and 7 drops of H2SO4...

Determine the theoretical yield in mL when 1.5 mL of 3,3-dimethyl-2-butanol and 7 drops of H2SO4 (conc) are heated together at 70 degrees C. The product will have a molecular weight of 84.16 g/mol and a density of .68 g/mL.

Expert Solution

theoritical yield = n moles of starting material * molecular wieht of product

=> strarting material moles n = weight (v *d) / molecular weight

= (1.5 * 0.812) / 102.18

= 1.218/ 102.18

= 0.0119 moles

t.y = 0.0119 * 84.16

= 1.00 g

queen_honey_blossom answered 2 years ago

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