In: Statistics and Probability
A random sample of college students was asked to respond to a survey about how they spend their free time on weekends. One question, summarized in the table below, asked each respondent to choose the one activity that they are most likely to participate in on a Saturday morning. The activity choices were homework, job, recreation, or other.
Homework |
Job |
Recreation |
Other |
|
Male |
29 |
35 |
23 |
9 |
Female |
18 |
43 |
39 |
4 |
a. If one student is randomly chosen from the group, what is the
probability that the student is male?
b. If one student is randomly chosen from the group, what is the
probability that the student chose "recreation" as their most
likely activity on a Saturday morning?
c. If one student is randomly chosen from the group, what is the
probability that the student is male and chose "job" as their most
likely activity on a Saturday morning?
d. If one student is randomly chosen from the group, what is the
probability that the student chose "recreation" or "other" as their
most likely activity on a Saturday morning?
e. If one student is randomly chosen from the group, what is the
probability that the student is female or chose "homework" as their
most likely activity on a Saturday morning?
f. Find the probability that a college student from the group chose
"homework" as their most likely activity on Saturday mornings given
that they are male.
Total = 29 + 35 + 23 + 9 + 18 + 43 + 39 + 4 = 200
a) P(male) = (29 + 35 + 23 + 9)/200 = 96/200 = 0.48
b) P(recreation) = (23 + 39)/200 = 62/200 = 0.31
c) P(male and job) = 35/200 = 0.175
d) P(recreation or other) = P(recreation) + P(other) - P(recreation and other)
= (62 + 13 - 0)/200 = 75/200 = 0.375
e) P(female or home work) = P(female) + P(home work) - P(female and home work)
= (104 + 47 - 18)/200 = 133/200 = 0.665
f) P(homework) = (29 + 18)/200 = 47/200 = 0.235