In: Chemistry
What would the potential of a standard hydrogen (S.H.E.) electrode be if it was under the following conditions?
[H+]=0.59M PH2 =3.0 atm T=298 K
The half reaction for Hydrogen electrode is 2 H+ +
e-
H2 (g)
We know that the potential under standard conditions is
0V ---> Eo = 0V
According to Nernst Equation ,
at 298 K
Given [H+] = 0.59M
pH2 = 3.0 atm
Conversion of pressure units to concentration :
We know that P = CRT
C = P / RT P = pressure = 3.0 atm
R = gas constant =0.0821 L atm /mol-K
T = temperature = 298 K
C = 3.0 / ( 0.0821 x 298 )
= 0.123 M
Plug the values we get