Question

In: Statistics and Probability

MPG Horsepower Weight 43.1 48 1985 19.9 110 3365 19.2 105 3535 17.7 165 3445 18.1...

MPG

Horsepower

Weight

43.1

48

1985

19.9

110

3365

19.2

105

3535

17.7

165

3445

18.1

139

3205

20.3

103

2830

21.5

115

3245

16.9

155

4360

15.5

142

4054

18.5

150

3940

27.2

71

3190

41.5

76

2144

46.6

65

2110

23.7

100

2420

27.2

84

2490

39.1

58

1755

28.0

88

2605

24.0

92

2865

20.2

139

3570

20.5

95

3155

28.0

90

2678

34.7

63

2215

36.1

66

1800

35.7

80

1915

20.2

85

2965

23.9

90

3420

29.9

65

2380

30.4

67

3250

36.0

74

1980

22.6

110

2800

36.4

67

2950

27.5

95

2560

33.7

75

2210

44.6

67

1850

32.9

100

2615

38.0

67

1965

24.2

120

2930

38.1

60

1968

39.4

70

2070

25.4

116

2900

31.3

75

2542

34.1

68

1985

34.0

88

2395

31.0

82

2720

27.4

80

2670

22.3

88

2890

28.0

79

2625

17.6

85

3465

34.4

65

3465

20.6

105

3380

  1. Determine the regression coefficient, b0, b1, and b2. State the multiple regression equation.
  2. Interpret the meaning of b0, b1, and b2.
  3. Explain why the regression coefficient b0 has no practical meaning in the context of this problem.
  4. Predict the miles per gallon for cars that have 60 horsepower and weight 2,000 pounds.
  5. If you were consulting for this organization and were provided these data to make a preliminary analysis, what would be your recommended next steps for the organization? (100 words)

Solutions

Expert Solution

I am using Excel to solve this problem.
First you copy data into excel then run regression

SUMMARY OUTPUT
Regression Statistics
Multiple R 0.865689
R Square 0.749417
Adjusted R Square 0.738754
Standard Error 4.176602
Observations 50
ANOVA
df SS MS F Significance F
Regression 2 2451.974 1225.987 70.28128 7.51E-15
Residual 47 819.8681 17.444
Total 49 3271.842
Coefficients Standard Error t Stat P-value Lower 95% Upper 95% Lower 95.0% Upper 95.0%
Intercept 58.15708 2.658248 21.87797 2.76E-26 52.80938 63.50479 52.80938 63.50479
Horsepower -0.11753 0.032643 -3.60028 0.000763 -0.1832 -0.05186 -0.1832 -0.05186
Weight -0.00687 0.001401 -4.90349 1.16E-05 -0.00969 -0.00405 -0.00969 -0.00405

1) So from the summary we can see that regression coefficients are as below:

b0 = 58.157082, b1 = -0.117525, b2 = -0.006871

So multiple regression equation is :

MPG = 58.157082 - 0.117525 * Horsepower - 0.006871 * Weight

2) b0 ---> When horsepower and weight both are 0, the MPG value is 58.157

b1 ---> For every one unit increase in Horsepower, the MPG value is expected to go down by 0.117525

b2 ---> For every one unit increase in Weight, the MPG value is expected to go down by 0.006871

3) Here the regression coefficent b0 has no practical meaning as this is practically impossible to have a car of zero weight and zero horsepower.

4) To predict using the above model, we can make use of the predict() function as below:

predict(model,newdata = data.frame(Horsepower = 60,Weight = 2000))

= 37.36427

So the model predicts 37.36427 mpg for a car having 60 horsepower and weighing 2000 pounds.

5) Next Step is:

We can use this model for prediction of miles per gallon for cars using horsepower and weight

As value of  horsepower and weight increases value of miles per gallon expected to go down.

Here the regression coefficent b0 has no practical meaning as this is practically impossible to have a car of zero weight and zero horsepower.

This two variable  horsepower and weight explains 74.94% variability in  horsepower and weight but still 25% variability unexplained.

So we can use other information to improve it further like age of car .Also we can use variable selection to improve model further like stepwise regression to choose best set of variable.based on adjusted R^2

==================================================

If you have any doubt please let me know through comment
Please give positive vote if you find this solution helpful. Thank you!


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