Question

1-

Assuming potato chip bag fill weights are normally distributed, consider a new random sample of n=5 fill weights. Do NOT use any prior mean and standard deviation assumptions. The new study fill weight data values are:

7.5 8.1 9.2 7.8 8.4

Test the null hypothesis that the population mean is 7.5 vs. the alternative that the population mean is GREATER than 7.5 oz. Use the 0.05 significance level.

Enter the P-VALUE.

Note: Enter X.XX AT LEAST ONE DIGIT BEFORE THE DECIMAL, TWO AFTER and round up. Thus, 27 is entered as 27.00, 3.5 is entered as 3.50, 0.3750 is entered as 0.38

2-

Enter the Critical Value from the appropriate book table for the above test of hypothesis. Use a 0.05 significance level.

Note: Enter X.XX AT LEAST ONE DIGIT BEFORE THE DECIMAL, TWO AFTER and round up. Thus, 27 is entered as 27.00, 3.5 is entered as 3.50, 0.3750 is entered as 0.38

3-

What is the conclusion of the above test? Use a 0.05 significance level. Enter 3 CAPITAL LETTERS:

REJ - Reject H0 in favor of H1

FTR - Fail to Reject H0

Answer 1

Claim: To test whether that population mean is greater than 7.5 oz or not

Hypothesis:  

Right tailed test

Test statistics:

Where

sample mean

sample SD =
OR sample standard deviation can calculated  by using excel as

Put all the data in excel worksheet then
use excel command

=STDEV.S(Select all the data)

we get sample standard deviation = s = 0.652

sample size = n = 5

Therefore test statistics is

i.e.

i.e.

we get test statistics

Degrees of freedom

Critical value: ...........(By using t table)

Decision Rule:     Reject Ho

Conclusion: There is sufficient evidence to conclude that population mean is greater than 7.5 oz