Question

Question 36

Assuming potato chip bag fill weights are normally distributed, consider a new random sample of n=5 fill weights. Do NOT use any prior mean and standard deviation assumptions. The new study fill weight data values are:

7.5 8.1 9.2 7.8 8.4

Test the null hypothesis that the population mean is 7.5 vs. the alternative that the population mean is GREATER than 7.5 oz. Use the 0.05 significance level.

Enter the P-VALUE.

Enter the Critical Value from the appropriate book table for the above test of hypothesis. Use a 0.05 significance level

What is the conclusion of the above test? Use a 0.05 significance level. Enter 3 CAPITAL LETTERS:

REJ - Reject H0 in favor of H1

FTR - Fail to Reject H0

Answer 1

H0: Null Hypothesis: = 7.5

HA: Alternative Hypothesis: 7.5

From the given data, the following statistics are calculated:

n = 5

= 41/5 = 8.2

s= 0.6519

SE = s/

= 0.6519/ = 0.2915

Test statistic is given by:

t = (8.2 - 7.5)/0.2915 = 2.4011

= 0.05

ndf = n - 1 = 5 - 1 = 4

One Tail - Right Side Test

From Table, critical value of T = 2.1318

Since calculated value of t = 2.4011 is greater than critical value of t = 2.1318, the difference is significant. Reject null hypothesis.

Conclusion:

The data support the claim that the population mean is greater than 7.5 oz.

t score = 2.4011

ndf = 4

By Technology,P - Value = 0.0371

Since P - Value is less than = 0.05, the difference is significant. Reject null hypothesis.

Conclusion:

The data support the claim that the population mean is greater than 7.5 oz.

Correct option:

REJ - Reject H0 in favor of H1