In: Accounting
Hi,
how can we do an EXERGY budget analysis on a Rankine cycle?
is there a specific formula to use dealing with enthalpy and
entropy to do the exergy budget analysis?
Basically, The exergy analysis is employed to evaluate the performance of the system based on the irreversibility that is occurring in every component of the Rankine Cycle system (as non-isentropic expansion and compression)
The analysis was performed under the following assumptions for every working fluid:
# The temperature from the solar collector (t8,sol) is 140°C;
# The ambient temperature is considered to be 20°C;
# The isentropic efficiency for the turbine was assumed to be 85%.
# The isentropic efficiency for the pump was assumed to be 60%.
The model described above was used to simulate the behaviour of the ORC system upon variation of the outlet temperature of the solar collector.
Parameters |
Units |
R123 |
SES 36 |
R 365 mfc |
Qpreheater |
[kW] |
10.96 |
12.50 |
11.83 |
Qevaporator |
[kW] |
11.39 |
9.49 |
10.39 |
Qsuperheater |
[kW] |
1.054 |
1.404 |
1.188 |
Qcondenser |
[kW] |
16.94 |
13.69 |
15.04 |
Wturbine |
[kW] |
3.942 |
3.701 |
3.725 |
Wpump |
[kW] |
0.155 |
0.144 |
0.105 |
mORC |
[kg/s] |
0.1007 |
0.1048 |
0.0787 |
WORC |
[kW] |
3.787 |
3.555 |
3.620 |
Results for t8,sol=140
Heat exchanger |
Condenser |
Turbine |
Pump |
|||||||||
R123 |
SES36 |
R236 |
R123 |
SES36 |
R236 |
R123 |
SES36 |
R236 |
R123 |
SES36 |
R236 |
|
ExF[kW] |
5.94 |
5.94 |
5.94 |
0.56 |
0.46 |
0.48 |
4.56 |
4.23 |
4.23 |
0.155 |
0.145 |
0.105 |
ExP[kW] |
5.35 |
5.42 |
5.25 |
0.42 |
0.34 |
0.37 |
3.94 |
3.70 |
3.72 |
0.005 |
0.006 |
0.003 |
I [kW] |
0.59 |
0.52 |
0.69 |
0.14 |
0.12 |
0.10 |
0.62 |
0.53 |
0.50 |
0.151 |
0.138 |
0.102 |
Formula for Enthalpy
ah = (h − hr) − Tr (s − sr)
Formula for Entropy
(∆S = ah/Tr)