In: Chemistry
Determine the pH of a 0.500 M HNO2 solution. Ka of HNO2 is 4.6 * 10-4.
1.82 |
1.67 |
2.67 |
0.30 |
Write the reaction of HNO2 with water and set up the ICE
HNO2 (aq) + H2O (l) ---- > NO2- (aq) + H3O + (aq)
I 0.500 0 0
C -x +x +x
E (0.500-x) x x
Use ka expression to find the value of x
Ka = 4.6 x 10-4 = x2/ ( 0.500-x)
Solve quadratic equation.
X2 = 4.5 x 10-4 ( 0.500-x)
x = 0.01478 = [H3O+]
we know pH = - log [H3O+]
therefore
pH = - log ( 0.01478)
= 1.82
So the pH = 1.82