In: Chemistry
Calculate the free energy released when FADH2 is oxidized by molecular O2 under standard conditions. Please show work
From the Standard Reduction potential Table
E'° = 0.031 V
deltaG'° = –n FE'° = (–2)(96.48 kJ/V.mol)(0.031 V) = –5.98176 kJ/mol.
1 kJ = 0.239006 kcal
–5.98176 kJ/mol = –(5.98176*0.239006) kcal/mol = 1.4297 kcal/mol
the free energy released when FADH2 is oxidized by molecular O2 under standard conditions = 1.4297 kcal/mol or –5.98176 kJ/mol