Question

In: Statistics and Probability

At an auto parts place, the inspection time for a vehicle is approximately normally distributed with...

At an auto parts place, the inspection time for a vehicle is approximately normally distributed with the mean 25 minutes and the standard deviation 3

minutes.

1. What is the probability that a randomly selected car's inspection time

is between 20 and 31 minutes? Round your answer to three decimal places.

2. The owner of this auto parts places will give a gift card to the customer if his

car takes more than the longest 5% of the inspection time. What is the required

inspection time to get a gift card? Round your answer to three decimal places.

3. This place also offers a free car wash and the relationship between the car's

inspection time and washing time can be written as

            inspection time = 1.5 x washing time + 2.5

What are the mean and variance of total {inspection and washing} time?

Solutions

Expert Solution

Answer:-

Given that:-

At an auto parts place, the inspection time for a vehicle is approximately normally distributed with the mean 25 minutes and the standard deviation 3

minutes.

1. What is the probability that a randomly selected car's inspection time

is between 20 and 31 minutes?

We need to compute . The corresponding z- values needed to be computed are:

Therefore, we get

2. The owner of this auto parts places will give a gift card to the customer if his

car takes more than the longest 5% of the inspection time. What is the required

inspection time to get a gift card?

The value of that solves the equation above cannot be made directly,it is solved either by looking at a standard normal distribution table or by approximation (the way Excel or this calculator does)

Based on this, we find that the solution is ,because from the normal table we see that

Therefore,the percentile we are looking for is computed using the following formula

  

3. This place also offers a free car wash and the relationship between the car's

inspection time and washing time can be written as

            inspection time = 1.5 x washing time + 2.5

What are the mean and variance of total {inspection and washing} time?

i=1.5*w+2.5

mean=E(i)=E(1.5*w2.5)=1.5*E(w)+2.5=1.5*25+2.5=40

Variance=V(i)=V(1.5*w+2.5)= *Var(w)+0=

Since Var(constant)=0


Related Solutions

At an auto parts place, the inspection time for a vehicle is approximately normally distributed with...
At an auto parts place, the inspection time for a vehicle is approximately normally distributed with the mean 25 minutes and the standard deviation 3 minutes. 1) What is the probability that a randomly selected car’s inspection time is between 20 and 31 minutes? Round your answer to three decimal places. 2) The owner of this auto parts places will give gift card to customer if his car takes more than the longest 5% of the inspection time. What is...
The time for visitor to read health instructions on a Web site is approximately normally distributed...
The time for visitor to read health instructions on a Web site is approximately normally distributed with a mean of 10 minutes and a standard deviation of 2 minutes. Suppose 64 visitors independently view the site. Determine the following: 1. Expected value and variance of the mean time of the visitors 2. Probability that the mean time of the visitors is within 15 seconds of 10 minutes 3. Value exceeded by the mean time of the visitors with probability 0.01.
0. The time required to install a new aircraft engine is approximately a normally distributed random...
0. The time required to install a new aircraft engine is approximately a normally distributed random variable with a mean of 20 hours and a standard deviation of 1 hour. What is the probability that the next installation takes a. Between 20 and 21.5 hours? b. Between 18 and 20 hours? c. Over 23 hours? d. At most 16.1 hours? e. More than 18.3 hours?
12. The production of auto component goes through the processes of parts production, assembly, inspection and...
12. The production of auto component goes through the processes of parts production, assembly, inspection and packaging. The time of each process is indicated in the diagram below (10 points) Part Production 100 units/30min Assembly Unit 100 units/20mins Inspection Unit 100units/10mins Packaging Unit 100 units/15min a. What is the cycle time of the process? b. What is the manufacturing lead time of each batch of 100 parts? c. If the work is carried out as indicated above (i) What would...
Vehicle speed on a particular bridge in China can be modeled as normally distributed. (a) If...
Vehicle speed on a particular bridge in China can be modeled as normally distributed. (a) If 5% of all vehicles travel less than 39.13 m/h and 10% travel more than 73.23 m/h, what are the mean and standard deviation of vehicle speed? (b) What is the probability that a randomly selected vehicle's speed is between 50 and 65 m/h? (c) What is the probability that a randomly selected vehicle's speed exceeds the speed limit of 70 m/h?
Vehicle speed on a particular bridge in China can be modeled as normally distributed. (a) If...
Vehicle speed on a particular bridge in China can be modeled as normally distributed. (a) If 5% of all vehicles travel less than 39.19 m/h and 10% travel more than 73.21 m/h, what are the mean and standard deviation of vehicle speed? (Round your answers to three decimal places.) mean standard deviation (b) What is the probability that a randomly selected vehicle's speed is between 50 and 65 m/h? (Round your answer to four decimal places.) (c) What is the...
The diameter of a brand of tennis balls is approximately normally​ distributed, with a mean of...
The diameter of a brand of tennis balls is approximately normally​ distributed, with a mean of 2.58 inches and a standard deviation of .04 inch. A random sample of 11 tennis balls is selected. Complete parts​ (a) through​ (d) below. a. What is the sampling distribution of the​ mean? A.Because the population diameter of tennis balls is approximately normally​ distributed, the sampling distribution of samples of size 11 will be the uniform distribution. B.Because the population diameter of tennis balls...
The diameter of a brand of tennis balls is approximately normally? distributed, with a mean of...
The diameter of a brand of tennis balls is approximately normally? distributed, with a mean of 2.79 inches and a standard deviation of 0.05 inch. A random sample of 10 tennis balls is selected. Complete parts? (a) through? (d) below. a. What is the sampling distribution of the? mean? A.Because the population diameter of tennis balls is approximately normally? distributed, the sampling distribution of samples of size 10 cannot be found. B.Because the population diameter of tennis balls is approximately...
Scores of a standardized test are approximately normally distributed with a mean of 85 and a...
Scores of a standardized test are approximately normally distributed with a mean of 85 and a standard deviation of 5.5. (a) What proportion of the scores is above 90? (b) What is the 25th percentile of the scores? (c) If a score is 94, what percentile is it on?
The amount of water in a bottle is approximately normally distributed with a mean of 2.85...
The amount of water in a bottle is approximately normally distributed with a mean of 2.85 litres with a standard deviation of 0.035-liter. b. If a sample of 4 bottles is​ selected, the probability that the sample mean amount contained is less than 2.82 ​litres is 0.043. c. If a sample of 25 bottles is​ selected, the probability that the sample mean amount contained is less than 2.82 ​litres is 0. Explain the difference in the results of​ (b) and​...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT