Question

In: Math

Complete the following table: (Use Table 15.1) (Do not round intermediate calculations. Round your answers to...

Complete the following table: (Use Table 15.1) (Do not round intermediate calculations. Round your answers to the nearest cent.)

First Payment
Broken Down Into—
Selling
price
Down payment Amount
mortgage
Rate Years Monthly
payment
Interest Principal Balance at end of month
$150,000 $30,000 $120,000 7% 30 $ $ $ $

Solutions

Expert Solution

The formula used to calculate the fixed monthly payment (P) required to fully amortize a loan of L dollars over a term of n months at a monthly interest rate of r is .

P = L[r(1 + r)n]/[(1 + r)n - 1]

Here, L = $ 120000, n = 30*12 = 360 and r = 7/1200 .

Hence P = 120000*(7/1200)[(1+7/1200)360]/[ (1+7/1200)360-1] = 700*8.116497466/7.116497466 = $ 798.36 ( on rounding off to the nearest cent). Also, $ 120000/360 = $333.33( on rounding off to the nearest cent). Hence, the amount of principal in the 1st repayment is $ 333.33 and the amount of interest is $ 798.36 -$333.33 = $ 465.03.The balance laft after this first repayment is $ 120000- $333.33 = $ 119666.67.

First Payment

Selling

Price

($)

Down Payment

($)

Amount

Mortgage

($)

Rate

(%)

Years

Monthly

Payment

($)

Broken down into

Interest     Principal

($)                 ($)

Balance at the end of the month($)

150000

30000

120000

7

30

798.36

465.03            333.33

119666.67


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