Question

In: Physics

A 60-kg base runner begins his slide into second base when he is moving at a...

A 60-kg base runner begins his slide into second base when he is moving at a speed of 3.0 m/s. The coefficient of friction between his clothes and Earth is 0.70. He slides so that his speed is zero just as he reaches the base.

(a) How much mechanical energy is lost due to friction acting on the runner?
J

(b) How far does he slide?
m

Solutions

Expert Solution

Given Info:

The mass of base runner is 60 kg.

The speed of base runner is 3.0 m/s.

The coefficient of friction between his cloth and earth is 0.70.

(a) The sum of all potential energy an object has and its kinetic energy is known as its mechanical energy. We can write this as, M=U+K ,where M, U and K represent mechanical energy, potential energy and kinetic energy, respectively.

According to the Work-Energy theorem, the net work done on an object is equal to the change in kinetic energy of the object.

W = KE​​​​​i - KE​​​​​f

KE​​​​​f is the finial kinetic energy and KE​​​​​i is the initial kinetic energy

Since, the base runners speed is zero just as he reaches the base; the finial kinetic energy of the base runner is zero. Thus, The energy lost due to friction is,

W = - 1/2 × m× vi ^2

W = -0.5 × 60× (3)^2

W = - 270 J _Ans.

(b) Ans = 0.655 m

​​​

genius_generous answered 2 years ago
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