Question

In: Math

Let L1 be the line passing through the point P1=(−1, −2, −4) with direction vector →d=[1,...

Let L1 be the line passing through the point P1=(−1, −2, −4) with direction vector →d=[1, 1, 1]T, and let L2 be the line passing through the point P2=(−2, 4, −1) with the same direction vector.
Find the shortest distance d between these two lines, and find a point Q1 on L1 and a point Q2 on L2 so that d(Q1,Q2) = d. Use the square root symbol '√' where needed to give an exact value for your answer.

Solutions

Expert Solution

Part i)

Line L1:

The point P1=<-1,-2,-4> with direction vector u=<1,1,1>

Line L2:

The point P2=<-2,4,-1> with direcion vector u=<1,1,1>

Since the direction vectors for L1 and L2 are same implies the lines L1 and L2 are parallel. The distance between parallel lines is

The line P1P2 is

The direction vector u is

Find the cross product of the vectors P1P2 and u

That is

The magntiude of the direction vector is

Therefore,

Part ii)

Let, Q1=P1=<-1,-2,-4>.

Any point on L2 is

Distance between the two points is

That is

Differentiate w.r.t t

That is

For minmum distance

Therefore, the point Q2 is

Distance between Q1 and Q2 is


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