A proton is accelerated for a period of 1/20 second in the direction of its initial...

A proton is accelerated for a period of 1/20 second in the direction of its initial motion by an electric field of 2 mV/m. At the end of this period it leaves the electric field and enters a
2.05 mT magnetic field which is perpendicular to its direction of motion. If the proton follows a circular path in the magnetic field with 15 cm radius, calculate the protons original speed just before it entered the electric field. (m_p = 1.67x10^-27 kg, e = 1.6x10^-19 C)

Expert Solution

Summary: First I calculated the speed of the proton before entering the magnetic fieldthen I calculated speed of proton before entering the electric field by applying equation of motion.

genius_generous answered 2 years ago

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