3. A proton is accelerated in a Van de Graff through a potential difference of 4...

3. A proton is accelerated in a Van de Graff through a potential difference of 4 million Volts.

a. What is its its total energy after acceleration?

b. What is the magnitude of its final momentum?

c. What is its velocity?

Solutions

Expert Solution

The charge on proton = e = 1.602 x 10^-19 C

The mass of the proton = 1.672 x 10^-27 kg

(a) The total energy of proton accelerated by a potential difference of 4 million volts is

(b) The total energy of the proton is kinetic energy. And kinetic energy is given by

Where m is mass, and v is velocity.

Putting all the known values in the kinetic energy equation, we get

or,

So, the momentum of this proton is

c. The velocity of the proton is 2.77 x 10⁷ m/s.

genius_generous answered 1 month ago

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