Question

In: Statistics and Probability

"Durable press" cotton fabrics are treated to improve their recovery from wrinkles after washing. "Wrinkle recovery...

"Durable press" cotton fabrics are treated to improve their recovery from wrinkles after washing. "Wrinkle recovery angle" measures how well a fabric recovers from wrinkles. Higher is better. Here are data on the wrinkle recovery angle (in degrees) for the same fabric specimens discussed in the previous exercise:

Permafresh Hylite
140 167
109 195
106 175
128 157
139

A manufacturer wants to know how large is the difference in mean wrinkle recovery angle.

  1. The mean and the standard deviation for the Permafresh are:

    ¯x=x¯= Round to 3 decimal places.

    s=s= Round to 3 decimal places.
  2. The mean and the standard deviation for the Hylite are:

    ¯x=x¯= Round to 3 decimal places.

    s=s= Round to 3 decimal places.
  3. The standard error is:

    SE = Round to 3 decimal places.

    The critical value from the distribution for a confidence interval of 95% is:

    t*= Use degrees of freedom of 3. Use Technology Round to 3 decimal places.
  4. Using the the answer from above (all rounded to 3 decimal places), calculate by hand a 95% confidence interval for the difference in mean wrinkle recovery angle:

    to . Hint Round to 3 decimal places.

Solutions

Expert Solution

a)

Sample #1   ---->   Permafresh
mean of sample 1,    x̅1=   124.400
standard deviation of sample 1,   s1 =    16.165

size of sample 1,    n1=   5
      
b)

Sample #2   ---->    Hylite
mean of sample 2,    x̅2=   173.500
standard deviation of sample 2,   s2 =    16.114

size of sample 2,    n2=   4

c)

std error , SE =    √(s1²/n1+s2²/n2) =    10.825

t-critical value , t* =    3.182 (excel formula =t.inv(α/2,df)

d)

margin of error, E = t*SE =    3.1824   *   10.825   =   34.45
                  
difference of means = x̅1-x̅2 =    124.4000   -   173.500   =   -49.100
confidence interval is                   
Interval Lower Limit = (x̅1-x̅2) - E =    -49.1000   -   34.4494   =   -83.549
Interval Upper Limit = (x̅1-x̅2) + E =    -49.1000   -   34.4494   =   -14.651

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