A lift accelerates upwards from rest to a speed of 5.5 m s−1 in a certain...

A lift accelerates upwards from rest to a speed of 5.5 m s−1 in a certain time, ∆t. At that time, the ratio of its kinetic energy to the gravitational potential energy it has acquired is 0.33. What is the value of the time interval, ∆t?

Solutions

Expert Solution

Gravitational acceleration = g = 9.8 m/²

Mass of the lift = m

Initial speed of the lift = V₁ = 0 m/s (At rest)

Final speed of the lift = V₂ = 5.5 m/s

Time period in which the the lift accelerates = t

Acceleration of the lift = a

Height gained by the lift as it accelerates = H

Potential energy acquired by the lift = PE

Kinetic energy acquired by the lift = KE = 0.33PE

t = 1.7 sec

Value of the time interval = 1.7 sec

genius_generous answered 1 year ago

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