A motorcycle accelerates uniformly from rest and reaches a linear speed of 22.8 m/s in a...

A motorcycle accelerates uniformly from rest and reaches a linear speed of 22.8 m/s in a time of 8.64 s. The radius of each tire is 0.266 m. What is the magnitude of the angular acceleration of each tire?

Expert Solution

Initial speed u = 0

Speed after 8.64 s is v = 22.8 m/s

Time t = 8.64 s

Accleration a = (v-u) / t

=(22.8-0) / 8.64

= 2.6388 m/s ²

Radius r = 0.266 m

the magnitude of the angular acceleration of each tire = a / r

= 2.6388/0.266 = 9.92 rad/s ²

genius_generous answered 2 years ago

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