Question
In: Statistics and Probability
Students taking Professor’s Angela Mazza’s Introduction to Marketing course spent an average of 1.5 hours to...
Students taking Professor’s Angela Mazza’s Introduction to Marketing course spent an average of 1.5 hours to complete an assignment with a standard deviation of 0.40 hours and it follows the normal probability distribution.
(a) Find the portion of the students who spent between 1.5 and 2.5 hours to complete an assignment.
(b) Find the portion of the students who spent more than 2.5 hours to complete an assignment.
(c) Find the portion of the students who spent between 2.5 and 2.7 hours to complete an assignment.
(d) Find the portion of the students who spent between 1 and 2.7 hours to complete an assignment.
Solutions
Expert Solution
(a)49.38 percent of students
spent between 1.5 and2.5 hours to complete an assignment.
(b) 0.62 percent of students spent more than 2.5 hours to complete an assignment.
(c) 0.485 percent of students spent between 2.5 and 2.7 hours to complete an assignment.
(d) 89.305 percent of students spent between 1 and 2.7 hours to complete an assignment.
orchestra answered 2 years agoRelated Solutions
please show work 3. Students taking Professor’s Angela Mazza’s Introduction to Marketing course spent an average...
please show work
3. Students taking Professor’s Angela Mazza’s Introduction to
Marketing course spent an average of 1.5 hours to complete an
assignment with a standard deviation of 0.40 hours and it follows
the normal probability distribution.
(a) Find the portion of the students who spent between 1.5 and
2.5 hours to complete an assignment.
(b) Find the portion of the students who spent more than 2.5
hours to complete an assignment.
(c) Find the portion of the students...
Suppose in a course, hours spent in a week to do homework by students follow normal...
Suppose in a course, hours spent in a week to do homework by
students follow normal distribution with mean μ and standard
deviation σ.
Let X be the number of hours spent in a week by a
randomly selected student. What is the probability that she spent
more than 0.53 standard deviation hours more than the population
average? i.e. find P(X ≥ μ+ 0.53 σ). [Answer
to 4 decimal places]
Tries 0/5
Suppose we randomly select n students from the...
1 attempt left!!!! Previously, an organization reported that teenagers spent 1.5 hours per day, on average,...
1 attempt left!!!!
Previously, an organization reported that teenagers spent 1.5
hours per day, on average, on the phone. However, now the
organization thinks that, the mean is higher. 45 randomly chosen
teenagers were asked how many hours per day they spend on the
phone. The sample mean was 1.45 hours with a sample standard
deviation of 0.30. Conduct a test using a significance level of
α=0.05
a. The test statistic
b. The critical value
c. is there is enough...
The number of hours 10 students spent studying for a test and their scores on that...
The number of hours 10 students spent studying for a test and
their scores on that test is represented in the table below.
Hours spent studying, x
0
2
4
5
5
5
6
7
8
9
Test scores, y
40
51
64
69
73
75
93
90
95
95
7) What amount of the variance in test score (y) do the hours
spent studying (x) account for this sample? (r2 =?) Interpret the
result in the context of the...
The number of hours 1010 students spent studying for a test and their scores on that...
The number of hours
1010
students spent studying for a test and their scores on that test
are shown in the table. Is there enough evidence to conclude that
there is a significant linear correlation between the data?
Use
alphaαequals=0.050.05.
Hours, x
00
11
22
44
44
55
55
66
77
88
Test score, y
4141
4040
5555
5656
6464
6666
7575
7878
8181
9797
LOADING...
Click here to view a table of critical values for Student's
t-distribution.
Setup...
The number of hours 10 students spent studying for a test and their scores on that...
The number of hours 10 students spent studying for a test and
their scores on that test are shown in the table. Is there enough
evidence to conclude that there is a significant linear correlation
between the data? Use alphaequals0.05.
Hours, x= 0 1 2 4 4 5 5 6 7 8 Test score, y= 41 40 51 56 65 70
76 70 84 97
1. Setup the hypothesis for the test.
2. Identify the critical value(s). Select the correct...
The number of hours 10 students spent studying for a test and their scores on that...
The number of hours 10 students spent studying for a test and
their scores on that test is represented in the table below.
Hours spent studying, x
0
2
4
5
5
5
6
7
8
9
Test scores, y
40
51
64
69
73
75
93
90
95
95
3) Describe the type of correlation and interpret the
correlation in the context of the data. Be specific in describing
the magnitude, direction, and strength of the relationship.
(12p)
4)...
The number of hours 10 students spent studying for a test and their scores on that...
The number of hours 10 students spent studying for a test and
their scores on that test are shown in the table. Is there enough
evidence to conclude that there is a significant linear correlation
between the data? Use alphaαequals= .01
X(hours) = top row; Y(score)=bottom row
0
1
2
3
4
4
5
6
7
8
41
46
52
50
65
68
75
85
82
91
Set up hypothesis test = ??
Critical Values = ??
Calculate test statistic;...
The number of hours spent studying by students on a large campus in the week before...
The number of hours spent studying by students on a large campus
in the week before the final exams follows a normal distribution
with standard deviation of 8.4 hours. A random sample of these
students is taken to estimate the population mean number of hours
studying.
a. How large a sample is needed to ensure that the probability
that the sample mean differs from the population mean by more than
2.0 hours is less than 0.05?
b. Without doing the...
A survey was conducted at a college to determine the number of hours students spent outside...
A survey was conducted at a college to determine the number of
hours students spent outside on weekends during the winter. For
students from cold weather climates, the results were M =
8, SD = 1.5. For students from warm-weather climates, the
results were M = 5, SD = 4.2. Explain what these
numbers mean to a person who has never had a course in statistics,
and suggest conclusions the person can draw from these results.
These conclusions use the...
ADVERTISEMENT
ADVERTISEMENT
Latest Questions
- Which subnet (network address) does host 25.17.102.51 255.255.248.0 belong to?
- Joe Dokes retired today with $1,000,000 in his retirement nest egg. If he followed a cash...
- how is biopsychosocial compatiable model in the future.
- Give at least 5 nursing interventions (with rationale) of nursing diagnosis: Health-seeking behaviors related to patient’s...
- The Wall Street Wizard Co. sold a stock market investing plan through the mail that made...
- Rotating bits in C This rotates bits to the left which means the bits that were...
- Implement a method that meets the following requirements: (a) Takes as parameter 1) an int array...
ADVERTISEMENT