In: Accounting
A machine costing $209,200 with a four-year life and an estimated $18,000 salvage value is installed in Luther Company’s factory on January 1. The factory manager estimates the machine will produce 478,000 units of product during its life. It actually produces the following units: 123,000 in 1st year, 124,100 in 2nd year, 121,200 in 3rd year, 119,700 in 4th year. The total number of units produced by the end of year 4 exceeds the original estimate—this difference was not predicted. (The machine must not be depreciated below its estimated salvage value.)
Required:
Compute depreciation for each year (and total depreciation of all years combined) for the machine under each depreciation method. (Round your per unit depreciation to 2 decimal places. Round your answers to the nearest whole dollar.)
Solution:
Straight line depreciation:
Year | Depreciation expenses |
1 | $47,800 |
2 | $47,800 |
3 | $47,800 |
4 | $47,800 |
Total | $191,200 |
Working:
Cost of machine =209,200
Salvage value = 18,000
Useful life =4
Depreciation = (Cost of machine -salvage value) /useful life
=($209,200 -$18,000)/4 years
=$47,800
Units of production:
Year | Depreciable units | Depreciation per unit | Depreciation expenses |
1 | 123,000 | $0.39 | $47,970 |
2 | 124,100 | $0.39 | $48,399 |
3 | 121,200 | $0.39 | $47,190 |
4 | 119,700 | $0.39 | $46,683 |
Total | $190,242 |
Working:
depreciation cost = $209,200 -$18,000 =$191,200.
Total depreciable units =123,000+124,100+121,200+119,700 =488,000
Depreciation per unit = $191,200/488,000 =$0.39
DDB depreciation for the period | End of period | ||||
Year | Beginning of period book value | Depreciation rate | Depreciation expenses | Accumulated depreciation | Book value |
1 | $209,200 | 50% | $104,600 | $104,600 | $104,600 |
2 | $104,600 | 50% | $52,300 | $156,900 | $52,300 |
3 | $52,300 | 50% | $26,150 | $183,050 | $26,150 |
4 | $26,150 | 50% | $13,075 | $196,125 | $18,000 |
Total | $196,125 |
Depreciation rate = 1/4*100*2 =50%
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